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Posted: June 15th, 2022
An observational study based on survey data concluded
An observational study based on survey data concluded that people who took morevitamin C had been in a position to get better from the flu quicker. You need to replicate this study utilizing anexperimental strategy. The remedy on this experiment is perhaps:Question Assignment 21 choices:how lengthy it takes to get better from the flu, in days.the change in physique temperature over the interval of the experiment.the quantity of vitamin C taken per day: zero mg, 1000 mg, 2000 mg, or 3000 mg.whether or not a person took vitamin C in a tablet kind or liquid kind.You conduct a speculation take a look at and discover a P-value of .025. Which of thefollowing is true?Question Assignment 22 choices:You may reject Ho on the .01 significance degree.You may reject Ho on the .05 significance degree.You may settle for Ho on the .05 significance degree.You may say the likelihood that Ho is true at p = .025.Which of the next is a crucial step in each speculation testing process utilizing a teststatistic?Question Assignment 23 choices:State the null and different hypotheses within the context of the issue.Compute the take a look at statistic and use it to seek out the p-value.State a conclusion in context of the issue.The entire above are steps in conducting a speculation take a look at.Compute a take a look at statistic for a random pattern with n = 23, s = 2.33, x(bar) = 15.5 for thetest Ho: µ =14.75, Ha: µ ≠ 14.75Question Assignment 24 choices:1.541.962.0741.717Suppose a study confirmed that the 4 hottest pizzas are most well-liked inthe following percentages:ToppingPercentCheese 24Pepper32oniSausag29eVeggie 15You determine to maintain observe of the following 150 pizzas of those sorts ordered at therestaurant the place you’re employed to see if the odds maintain true. That is thedata you get at your restaurant:ToppingObservedNumberCheese 41Pepper55oniSausag36eVeggie 18Discover the chi-square statistic and the related P-value for a speculation testwhere the null speculation is that the distribution of pizza toppings is asreported within the study, and the place the choice speculation is that thedistribution of pizza toppings is totally different from that reported within the study.Question Assignment 25 choices:X2 = 150.5, P = 0X2 = three.908, P = .419X2 = three.908, P = .097X2 = three.908, P = .272
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