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Posted: January 28th, 2022
Peer Response 1 essay
· Your response must be a minimum of 50 phrases
PEERS RESPONSE:
I hope everybody had a protected and wholesome New Yr’s. I’m #20 for this week’s dialogue; issues #28 and # 40.
I’ll begin with # 28) 16, Consider the Expression Utilizing the Technique a
Step one is to write down 16 as an ideal sq.. The principal sq. root of 16 could be four.
So, = (42)
Subsequent, I have to eradicate the exponents utilizing the rule of exponents (xa)b=x(a⋅b) ……..a=2, b=three/2
= (42) = 43 the exponents 2 and denominator 2 are eradicated which leaves me with =43. Last step is to unravel four to the third energy which equals 64. That is my reply.
For the second drawback, #40) three 5
To resolve I used the product rule for radicals as a result of each radicals are of the identical index. The nth root of a product can be equal to the product of the nth roots.
First, I have to get all radicals below a single sq. root. This could seem like:
Subsequent is to multiply three by 6, then add the exponents three&5.
= That is the novel type. This nonetheless must be simplified. Issue out the phrases.
Now 18 and b8 must be written as a a number of of an ideal sq.. The 2 numbers whose product is 18 could be 9*2 and the 2 numbers whose product is eight is four*2. So, I get the next:
= 2 To simplify I need to cancel exponents and the sq. root.
= 2 The sqrt of 9 is three^2, =
=3b4 Lastly, we have to reorder the phrases to get,
= three That is the reply.
Thanks, Erica
No less than 50 phrases must be included in your response.
RESPONSE OF PEERS:
I want everybody a cheerful and wholesome New Yr’s Eve. For this week’s dialog, I’m #20, with difficulties #28 and #40.
# 28) 16, Consider the Expression Utilizing the Technique a
Step one is to write down 16 in sq. type. four is the first sq. root of 16.
Consequently, = (42)
Subsequent, I have to eradicate the exponents utilizing the rule of exponents (xa)b=x(a⋅b) ……..a=2, b=three/2
= (42) = 43 the exponents 2 and denominator 2 are eradicated which leaves me with =43. Last step is to unravel four to the third energy which equals 64. That is my reply.
For the second drawback, #40) three 5
To resolve I used the
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