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Posted: April 20th, 2022
proportions and confidence intervals
Question Assignment description
In a random pattern, 136 of 400 individuals given a flu vaccine skilled some discomfort.I used to be requested to arrange a 95% confidence interval for the true proportion of individuals who will expertise some discomfort. The issue is solved by I need Helpance with interpretation.
Now we have p = zero.34, n = 400, and z = 1.96 for 95%
confidence.
Interval = zero.34 ± 1.96√[(0.34)(0.66)/400]
= zero.34 ± 1.96√zero.000561
= zero.34 ± 1.96(zero.023685439)
=
(zero.29357654, zero.38642346)
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