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Posted: January 28th, 2022

Peer Response 1 essay

· Your response must be a minimum of 50 phrases

PEERS RESPONSE:

I hope everybody had a protected and wholesome New Yr’s. I’m #20 for this week’s dialogue; issues #28 and # 40.

I’ll begin with # 28) 16, Consider the Expression Utilizing the Technique a

Step one is to write down 16 as an ideal sq.. The principal sq. root of 16 could be four.

So, = (42)

Subsequent, I have to eradicate the exponents utilizing the rule of exponents (xa)b=x(a⋅b) ……..a=2, b=three/2

= (42) = 43 the exponents 2 and denominator 2 are eradicated which leaves me with =43. Last step is to unravel four to the third energy which equals 64. That is my reply.

For the second drawback, #40) three 5

To resolve I used the product rule for radicals as a result of each radicals are of the identical index. The nth root of a product can be equal to the product of the nth roots.

First, I have to get all radicals below a single sq. root. This could seem like:

Subsequent is to multiply three by 6, then add the exponents three&5.

= That is the novel type. This nonetheless must be simplified. Issue out the phrases.

Now 18 and b8 must be written as a a number of of an ideal sq.. The 2 numbers whose product is 18 could be 9*2 and the 2 numbers whose product is eight is four*2. So, I get the next:

= 2 To simplify I need to cancel exponents and the sq. root.

= 2 The sqrt of 9 is three^2, =

=3b4 Lastly, we have to reorder the phrases to get,

= three That is the reply.

Thanks, Erica

No less than 50 phrases must be included in your response.

RESPONSE OF PEERS:

I want everybody a cheerful and wholesome New Yr’s Eve. For this week’s dialog, I’m #20, with difficulties #28 and #40.

# 28) 16, Consider the Expression Utilizing the Technique a

Step one is to write down 16 in sq. type. four is the first sq. root of 16.

Consequently, = (42)

Subsequent, I have to eradicate the exponents utilizing the rule of exponents (xa)b=x(a⋅b) ……..a=2, b=three/2

= (42) = 43 the exponents 2 and denominator 2 are eradicated which leaves me with =43. Last step is to unravel four to the third energy which equals 64. That is my reply.

For the second drawback, #40) three 5

To resolve I used the

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